jeanbaudrillard-deactivated2012 asked: If you still need help on that calculus, problem, here's a solution. Multiply the whole function by 2/2. You're doing this because as long as you have lim (x->0) (sinbx/bx) where b is any number, the limit would be one. So by multiplying by 2/2, you're keeping the value the same because 2/2 = 1. So you have: lim (x->0) (2sin(2x)) divided by 2x. The lim (x->0) of sin2x/2x = 1, so you are now left with 2. So 2*1 = 2. I hope that helps. I tried to be very clear. :D
This helps a lot! Thanks so much :) Seriously, lol I was so lost on this one. You were really clear, much clearer than all the stupid Google answers. Haha, thanks again for your help!